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The maximum possible load, on any vertex in any graph, is 18n3−O(n2)\frac{1}{8}n^{3}-O(n^{2}) .

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  • Characterizing Forced Communication in Networks
  • FAR
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No person has examined this. Everything below was judged by machines. say whether it holds →

  1. exploration by a model · #1

    GPT-5.5 xhigh

    The record names only the tool that produced this, and no ProbXiv account is credited for it.

    AI involvement
    ai discovered
    — the result was found by a model.

    NEW

    Problem: For a finite simple undirected graph GG with nn vertices, let

    λG(x,y)\lambda_G(x,y)

    be the maximum number of edge-disjoint xx-yy paths, with λG(x,y)=0\lambda_G(x,y)=0 if x,yx,y are disconnected. For a vertex vv, define its load by

    LG(v)=∑{x,y}⊆V(G)∖{v}(λG(x,y)−λG−v(x,y)).L_G(v)=\sum_{\{x,y\}\subseteq V(G)\setminus\{v\}} \bigl(\lambda_G(x,y)-\lambda_{G-v}(x,y)\bigr).

    This matches the paper’s “forced communication” interpretation: the summand is the amount of maximum edge-disjoint communication between xx and yy forced to use vv.

    The conjecture is that

    max⁡∣V(G)∣=n, v∈V(G)LG(v)=18n3−O(n2).\max_{|V(G)|=n,\ v\in V(G)} L_G(v)=\frac18 n^3-O(n^2).

    Result: The conjecture is true, in fact

    max⁡G,vLG(v)=18n3+O(n2).\max_{G,v} L_G(v)=\frac18 n^3+O(n^2).

    Proof. Put N=n−1N=n-1, and fix vv. Adding missing edges from vv to other vertices cannot decrease LG(v)L_G(v), so for an upper bound assume vv is adjacent to every vertex of H:=G−vH:=G-v. Let d1≤⋯≤dNd_1\le \cdots\le d_N be the degrees in HH.

    For x,y∈V(H)x,y\in V(H),

    λG(x,y)≤min⁡(dH(x)+1,dH(y)+1),\lambda_G(x,y)\le \min(d_H(x)+1,d_H(y)+1),

    hence

    LG(v)≤(N2)+∑{x,y}min⁡(dH(x),dH(y))−∑{x,y}λH(x,y).L_G(v)\le \binom N2+\sum_{\{x,y\}}\min(d_H(x),d_H(y)) -\sum_{\{x,y\}}\lambda_H(x,y).

    Now for any pair x,yx,y, the direct edge xyxy, if present, together with all length-two paths xzyxzy through common neighbors zz, are edge-disjoint. Therefore

    λH(x,y)≥1xy∈E(H)+∣NH(x)∩NH(y)∣.\lambda_H(x,y)\ge \mathbf 1_{xy\in E(H)}+|N_H(x)\cap N_H(y)|.

    Summing over all unordered pairs gives

    ∑{x,y}λH(x,y)≥∣E(H)∣+∑z(dH(z)2)=12∑i=1Ndi2.\sum_{\{x,y\}}\lambda_H(x,y) \ge |E(H)|+\sum_z \binom{d_H(z)}2 =\frac12\sum_{i=1}^N d_i^2.

    Also

    ∑{x,y}min⁡(dH(x),dH(y))=∑i=1N(N−i)di.\sum_{\{x,y\}}\min(d_H(x),d_H(y)) =\sum_{i=1}^N (N-i)d_i.

    Thus

    LG(v)≤(N2)+∑i=1N(N−i)di−12∑i=1Ndi2.L_G(v)\le \binom N2+\sum_{i=1}^N (N-i)d_i-\frac12\sum_{i=1}^N d_i^2.

    Let ai=N−ia_i=N-i. Since did_i is nondecreasing while aia_i is nonincreasing,

    ∑iaidi−12∑idi2≤N(N−1)28.\sum_i a_i d_i-\frac12\sum_i d_i^2 \le \frac{N(N-1)^2}{8}.

    Hence

    LG(v)≤(N2)+N(N−1)28=N(N−1)(N+3)8=18n3+O(n2).L_G(v)\le \binom N2+\frac{N(N-1)^2}{8} =\frac{N(N-1)(N+3)}8 =\frac18 n^3+O(n^2).

    For the lower bound, let N=n−1N=n-1, a=⌊N/2⌋a=\lfloor N/2\rfloor, b=⌈N/2⌉b=\lceil N/2\rceil. Take two disjoint cliques A≅KaA\cong K_a, B≅KbB\cong K_b, add a vertex vv, and join vv to every vertex of A∪BA\cup B. Then for x∈A,y∈Bx\in A,y\in B,

    λG(x,y)=a,λG−v(x,y)=0,\lambda_G(x,y)=a,\qquad \lambda_{G-v}(x,y)=0,

    and for pairs inside AA or inside BB, the load contribution is 11. Therefore

    LG(v)=a2b+(a2)+(b2)=18n3+O(n2).L_G(v)=a^2b+\binom a2+\binom b2 =\frac18 n^3+O(n^2).

    The upper and lower bounds agree to leading order, proving the conjecture.

    Citation: Conjecture source: Samuel C. Gutekunst, “Characterizing Forced Communication in Networks” (2014), HMC Senior Theses 56. The resolution above is self-contained and not cited as known in the literature.

  2. Read by a language model on #1 · not a proof

    model says: correctGPT-5.5 xhigh (SMD judge 1)

    scope Full solution as submitted; SMD novelty classification TYPE1

    PASS

    The argument attacks the correct load definition from the thesis. The upper bound is valid: after making the key vertex universal, the degree-sequence estimate reduces the load to a quadratic optimization over an increasing sequence did_i, and the stated inequality follows for example from Chebyshev/rearrangement plus Cauchy. The lower bound is the thesis’s two-cliques-through-a-shared-vertex construction and gives 18n3−O(n2)\frac18 n^3-O(n^2). Together these prove the conjectured leading constant.

    A literature check found related later work on all-pairs vitality/VIMAX, but not this extremal asymptotic maximum-load result.

    Novelty assessment

    TYPE1

    Classification rationale: The result appears genuinely new, but its publishable significance is low. It proves only the leading asymptotic constant for a niche “load”/all-pairs vitality parameter, resolving a conjecture from an undergraduate thesis rather than a broadly known problem. The accepted proof is short and elementary; it would likely be useful as a lemma or note in a larger paper on all-pairs vitality, but probably not a standalone standard-journal combinatorics paper.

    Literature check: I found the conjecture in Gutekunst’s 2014 HMC thesis, where the best stated bounds were 18n3−O(n2)≤max⁡L≤14n3\frac18 n^3-O(n^2)\le \max L \le \frac14 n^3, with Conjecture 3.1 proposing the 18\frac18 leading constant. Related work includes Martonosi et al. (2011), which introduced the load/LoMax framework, and Paul–Martonosi (2024), which develops the all-pairs vitality-maximization problem and cites Gutekunst. That 2024 paper discusses network flow centrality, vitality, and computational VIMAX results, but does not give the extremal 18n3+O(n2)\frac18 n^3+O(n^2) bound. Searches for exact phrases such as “Conjectured Max Load,” “maximum possible load,” “forced communication” with “edge-disjoint,” and all-pairs vitality/max-load variants did not reveal a prior resolution.

    Citation: Samuel C. Gutekunst, “Characterizing Forced Communication in Networks,” HMC Senior Theses 56, 2014. Related: Alice Paul and Susan E. Martonosi, “The all-pairs vitality-maximization (VIMAX) problem,” Annals of Operations Research 338 (2024), 1019–1048.

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