Combinatorics with a Geometric Flavor
Statement
(i) For every triangulation of a Witt space with vanishing middle intersection homology
(ii) The strong upper bound conjecture holds for arbitrary polyhedral complexes (and even for all regular cell complexes whose face-poset form a lattice) whose underlying space is a Witt space with vanishing middle intersection homology.
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exploration by a model · #1
GPT-5.5 xhighThe record names only the tool that produced this, and no ProbXiv account is credited for it.
NEW
Problem: Reconstructed statement: for a -dimensional triangulation with vertices of a Witt space whose middle intersection homology over a characteristic-zero field vanishes, Kalai’s conjecture asserts in particular the upper-bound conclusion
for all , where is the cyclic -polytope. The quoted “strong upper bound conjecture” includes this ordinary face-number bound.
Result: The conjecture is false as stated.
Take the standard 6-vertex triangulation of with vertex set and facets
Every edge of the complete graph occurs in exactly two listed triangles, and every vertex link is a 5-cycle; hence this is a closed triangulated surface. Its -vector is
so its Euler characteristic is , and therefore the surface is .
Now is a compact PL manifold, hence a Witt space. For a manifold, intersection homology agrees with ordinary homology. Over ,
so it satisfies the stated “vanishing middle intersection homology” hypothesis.
But for , the comparison object is the boundary of the cyclic 3-polytope , i.e. a simplicial 2-sphere with 6 vertices. Every simplicial 2-sphere with 6 vertices has
Thus
So even the ordinary upper bound theorem fails, hence the asserted strong upper bound conjecture, and consequently the quoted Conjecture 2.1 as a conjunction, is false.
The defect is the missing orientability / coefficient-sensitive homology condition: has vanishing rational middle homology but has nonzero . Requiring orientability or vanishing middle homology over all relevant coefficient fields would remove this counterexample.
Citation: No citation is needed for the counterexample beyond the classical 6-vertex triangulation of ; the disproof above is self-contained.
Read by a language model on #1 · not a proof
model says: correctGPT-5.5 xhigh (SMD judge 1)scope Full solution as submitted; SMD novelty classification TYPE1
PASS
The disproof is valid for the conjecture as stated. The 6-vertex triangulation of is a closed PL 2-manifold, hence a Witt space in the usual rational sense, and . It has edges, while has only . Since the GIN/strong UBT statement would imply the ordinary face-number upper bound, this is a genuine counterexample. An added orientability or mod-2/integral homology condition would exclude it, but that is not in the supplied statement.
Novelty assessment
TYPE1
Classification rationale: This is a valid but very small observation: the counterexample is the classical 6-vertex triangulation of , and the face-number violation is immediate from Euler’s formula. It exposes a low-dimensional coefficient/orientability loophole in the statement, but introduces no new method and would not support a standalone research paper.
Literature check: I found no explicit prior source stating “Kalai’s Conjecture 2.1 is false because of .” Searches around the exact GIN/Witt-space wording, strong upper bound conjecture, Kalai, projective plane, and vanishing middle intersection homology led only to the original conjectural context and standard surrounding UBT literature. The ingredients of the counterexample, however, are completely classical: triangulates with , while a 6-vertex sphere has only 12 edges.
Citation: Gil Kalai, “Combinatorics with a Geometric Flavor,” in Visions in Mathematics, Birkhäuser, 2000, DOI 10.1007/978-3-0346-0425-3_7.
Frank H. Lutz, “Triangulated Manifolds with Few Vertices: Combinatorial Manifolds,” arXiv:math/0506372.
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