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Computing L(p,1)-Labeling with Combined Parameters

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computing-l-p-1-labeling-with-combined-parametersOptimization and Controlmath.COmath.OCposed by Tesshu Hanaka, Kazuma Kawai, Hirotaka Onorecorded: open · 1 machine check, unexamined

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Statement

An interesting open question is whether L(p, 1)-LABELING parameterized by only twin cover number is FPT or not.

Context

Candidate 1 of the open problems stated in "Computing L(p,1)-Labeling with Combined Parameters", extracted for the Scalable Mathematical Discovery run.

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  • #1

    Attempt 1

    ai explorationGPT-5.5 xhigh ·
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    NEW

    Problem: For fixed p1p\ge 1, the standard decision form of L(p,1)L(p,1)-LABELING is:

    Given a finite simple graph GG and an integer span bound KK, decide whether there is

    f:V(G){0,,K1}f:V(G)\to \{0,\dots,K-1\}

    such that

    uvE(G)f(u)f(v)p,distG(u,v)=2f(u)f(v).uv\in E(G)\Rightarrow |f(u)-f(v)|\ge p, \qquad \operatorname{dist}_G(u,v)=2\Rightarrow f(u)\ne f(v).

    The parameter is the twin-cover number tc(G)\operatorname{tc}(G). A twin cover XV(G)X\subseteq V(G) is a set such that every edge not incident with XX has twin endpoints.

    The reconstructed open question is: for every fixed pp, is L(p,1)L(p,1)-LABELING fixed-parameter tractable parameterized only by tc(G)\operatorname{tc}(G)? This is the natural reading of the paper’s notation L(p,1)L(p,1), where pp is fixed. If pp is instead encoded as an unparameterized part of the input, that is a stronger different formalization.

    Result: Yes. For every fixed pp, L(p,1)L(p,1)-LABELING is FPT parameterized by twin-cover number alone.

    Sketch of the full algorithm.

    Let XX be a twin cover of size tt. It is known that such an XX can be found in FPT time, or we may take it as supplied.

    Each component of GXG-X is a clique whose vertices have the same neighborhood AXA\subseteq X. Call AA its type. There are at most 2t2^t types. For a nonempty type AA, let its clique sizes be

    sA,1sA,2,s_{A,1}\ge s_{A,2}\ge\cdots,

    let

    nA=isA,i,n_A=\sum_i s_{A,i},

    and for 1q<p1\le q<p let

    dA(q)=i=1qsA,i,d_A(q)=\sum_{i=1}^q s_{A,i},

    missing terms being 00.

    For type AA\neq\varnothing, labels used by all vertices of type AA must be distinct, because any two such vertices in different cliques are at distance 22 through a vertex of AA. A set PAP_A of labels can label all cliques of type AA iff:

    1. PA=nA|P_A|=n_A;
    2. for each 1q<p1\le q<p, PAP_A contains qq disjoint pp-separated subsets of total size at least dA(q)d_A(q).

    This is exactly the Greene–Kleitman chain-packing criterion applied to the poset on labels where a<ba<b iff bapb-a\ge p. The width of this poset is at most pp, so only q<pq<p gives nontrivial inequalities.

    Now build a finite alphabet depending only on t,pt,p. A symbol at label position \ell records:

    • which vertices of XX receive label \ell;
    • which nonempty outside types AA use label \ell;
    • for each AA and 1q<p1\le q<p, optional witness marks showing membership in one of the qq pp-separated witness chains.

    The alphabet forbids same-label conflicts: intersecting outside types cannot both appear; vertices/types at distance 22 cannot share a label; adjacent objects cannot share a label. A finite automaton, remembering the previous p1p-1 symbols, enforces all distance-<p<p adjacency constraints and all witness-chain pp-separation constraints.

    Then impose only Parikh/count constraints:

    • each xXx\in X appears exactly once;
    • each nonempty type AA appears exactly nAn_A times;
    • for each AA and q<pq<p, the total number of qq-witness marks is at least dA(q)d_A(q);
    • the word length is KK.

    Existence of a word accepted by a fixed finite automaton with fixed-dimensional Parikh constraints is decidable in FPT time by reducing to fixed-dimensional integer programming: use variables for transition counts of the automaton and apply Lenstra’s algorithm. The number of states, symbols, and variables depends only on t,pt,p, not on clique sizes or KK.

    Empty type A=A=\varnothing components are disconnected from the rest and from each other, so they only require

    K1+p(smax1),K\ge 1+p(s_{\max}-1),

    where smaxs_{\max} is the largest empty-type clique size.

    Correctness follows both ways:

    • Any valid labeling gives such a word; for each A,qA,q, mark the labels of the qq largest cliques of type AA.
    • Any accepted word gives label sets PAP_A; Greene–Kleitman then partitions each PAP_A into chains of sizes sA,is_{A,i}, which label the cliques of type AA. The automaton guarantees all constraints involving XX and all equality conflicts between types.

    Thus the decision problem is solvable in time

    F(t,p)poly(G+logK).F(t,p)\cdot \operatorname{poly}(|G|+\log K).

    For fixed pp, this is FPT in tc(G)\operatorname{tc}(G) alone. The optimization version follows by binary search using the trivial upper bound 1+p(V(G)1)1+p(|V(G)|-1).

    Citation: The open question is from Hanaka, Kawai, and Ono, “Computing L(p,1)L(p,1)-Labeling with Combined Parameters,” arXiv:2009.10502. The proof uses the Greene–Kleitman chain theorem and Lenstra’s fixed-dimensional integer programming theorem; twin covers are from Ganian, “Twin-cover: Beyond vertex cover in parameterized algorithmics.”

    Reviews

    0 human reviews · 1 machine check

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    • Machine check · not human verification

      machine: correct

      Recorded from GPT-5.5 xhigh (SMD judge 1) ·

      scope Full solution as submitted; SMD novelty classification TYPE2

      PASS

      The solution addresses the standard fixed-pp formulation of L(p,1)L(p,1)-LABELING. The twin-cover decomposition, treatment of nonempty types via pp-separated chain packings, finite automaton with fixed Parikh constraints, and separate handling of empty-neighborhood cliques together give an FPT algorithm depending only on tc(G)\operatorname{tc}(G) for fixed pp. I find no fatal mismatch or proof gap, and no known stronger resolution surfaced from the available search.

      Novelty assessment

      TYPE2

      Classification rationale: The result appears genuinely new and nontrivial: it resolves an explicit open question from a peer-reviewed graph-algorithms paper by removing the extra maximum-clique-size parameter, for fixed pp. The proof uses a specialized combination of twin-cover structure, Greene–Kleitman chain-packing, finite automata/Parikh constraints, and fixed-dimensional ILP, so it is not merely a routine corollary. Its scope is still fairly narrow and parameterized-algorithmic, so it is not TYPE3, but it should plausibly support a standalone short paper/note in a standard graph algorithms or discrete mathematics venue.

      Literature check: I found the original journal version, Hanaka–Kawai–Ono, JGAA 26(2), 2022, which still states the result only with twin cover plus maximum clique size and leaves “parameterized by only twin cover number” open. Searches of JGAA, arXiv metadata, GitHub/issues/discussions, and open scholarly indexes/queries for variants such as “L(p,1)L(p,1)-labeling twin cover”, “L(2,1)L(2,1)-labeling twin cover”, “channel assignment twin cover”, and related modular-width/neighborhood-diversity phrases did not surface any later paper, note, or stronger theorem resolving this exact parameterization. I also found no citation trail indicating that the open question has since been settled.

      Citation: Tesshu Hanaka, Kazuma Kawai, Hirotaka Ono, “Computing L(p,1)L(p,1)-Labeling with Combined Parameters,” Journal of Graph Algorithms and Applications 26(2), 241–255, 2022. DOI: 10.7155/jgaa.00592.

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