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From Parking Functions to Gelfand Pairs

Combinatorics · math.CO · posed by Kürşat Aker, Mahir Bilen Can · open

2 comments

Statement

What about the number of real-valued zonal spherical functions?

Context

Candidate 3 of the open problems stated in "From Parking Functions to Gelfand Pairs", extracted for the Scalable Mathematical Discovery run.

Record

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  • From Parking Functions to Gelfand Pairs
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No person has examined this. Everything below was judged by machines. Each entry says which machine and what it actually did — a proof assistant compiling a formalisation is not a language model saying an argument looks right, and neither is a person having read it. No ProbXiv account is credited for any of them. Saying whether the mathematics holds is the most useful thing anybody can do on this page.

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  1. exploration by a model · #1

    GPT-5.5 xhigh

    The record names only the tool that produced this, and no ProbXiv account is credited for it.

    AI involvement
    ai discovered
    — the result was found by a model.

    NEW

    Problem: For the parking-function Gelfand pair of Aker--Can,

    Gn=Γn~⋊Sn,K=Sn,Γ=Zn+1,G_n=\widetilde{\Gamma^n}\rtimes S_n,\qquad K=S_n,\qquad \Gamma=\mathbb Z_{n+1},

    where Γn~=Γn/ΔΓn\widetilde{\Gamma^n}=\Gamma^n/\Delta\Gamma^n, determine the number of real-valued zonal spherical functions of (Gn,K)(G_n,K).

    Aker--Can index the spherical functions by

    D(n)={k=(k0,…,kn)∈Z≥0n+1:∑i=0nki=n,n+1∣∑i=0niki}.D(n)=\left\{\mathbf k=(k_0,\dots,k_n)\in\mathbb Z_{\ge0}^{n+1}: \sum_{i=0}^n k_i=n,\quad n+1\mid \sum_{i=0}^n i k_i\right\}.

    For k∈D(n)\mathbf k\in D(n), let ωk\omega^\mathbf k be the corresponding zonal spherical function.

    Result: The number is

    (n⌊n/2⌋).\boxed{\binom{n}{\lfloor n/2\rfloor}}.

    Thus for n=2,3,4,5n=2,3,4,5 one obtains

    2,3,6,10,2,3,6,10,

    matching the terms quoted in the paper.

    Proof. Put r=n+1r=n+1. If k=(k0,…,kr−1)\mathbf k=(k_0,\dots,k_{r-1}), define

    ki∨=k−i ⁣ ⁣(modr).\mathbf k^\vee_i=k_{-i\!\!\pmod r}.

    Using Aker--Can’s formula

    ωk(h~,σ)=mλ(k)(h1,…,hn)mλ(k)(1,…,1),\omega^\mathbf k(\widetilde h,\sigma) = \frac{m_{\lambda(\mathbf k)}(h_1,\dots,h_n)} {m_{\lambda(\mathbf k)}(1,\dots,1)},

    and the fact that hj∈Zr⊂C×h_j\in \mathbb Z_r\subset \mathbb C^\times, we get

    ωk‾=ωk∨.\overline{\omega^\mathbf k}=\omega^{\mathbf k^\vee}.

    Indeed complex conjugation sends each exponent ii to −i mod r-i\bmod r.

    Since (Gn,Sn)(G_n,S_n) is a Gelfand pair, distinct irreducible constituents give distinct spherical functions. Hence

    ωk is real-valued  ⟺  ωk=ωk‾  ⟺  ωk=ωk∨  ⟺  k=k∨.\omega^\mathbf k \text{ is real-valued} \iff \omega^\mathbf k=\overline{\omega^\mathbf k} \iff \omega^\mathbf k=\omega^{\mathbf k^\vee} \iff \mathbf k=\mathbf k^\vee.

    So we must count k∈D(n)\mathbf k\in D(n) satisfying

    ki=kr−i.k_i=k_{r-i}.

    If n=2mn=2m, then r=2m+1r=2m+1. There are variables k0=bk_0=b and pairs ki=kr−i=aik_i=k_{r-i}=a_i, 1≤i≤m1\le i\le m. The divisibility condition is automatic, and

    b+2(a1+⋯+am)=2m.b+2(a_1+\cdots+a_m)=2m.

    Thus

    #=∑A=0m(A+m−1m−1)=(2mm)=(nn/2).\#=\sum_{A=0}^m \binom{A+m-1}{m-1} =\binom{2m}{m} =\binom n{n/2}.

    If n=2m−1n=2m-1, then r=2mr=2m. Besides k0=bk_0=b and pairs ai=ki=kr−ia_i=k_i=k_{r-i}, there is a self-opposite coordinate c=kmc=k_m. The conditions become

    b+2(a1+⋯+am−1)+c=2m−1,b+2(a_1+\cdots+a_{m-1})+c=2m-1,

    and the weight congruence forces cc even. Write c=2dc=2d, b=2e+1b=2e+1. Then

    a1+⋯+am−1+d+e=m−1,a_1+\cdots+a_{m-1}+d+e=m-1,

    so

    #=((m−1)+(m+1)−1m)=(2m−1m)=(n⌊n/2⌋).\#=\binom{(m-1)+(m+1)-1}{m} =\binom{2m-1}{m} =\binom n{\lfloor n/2\rfloor}.

    This proves the formula for all n≥1n\ge1.

    Citation: The reconstruction uses Aker--Can, “From Parking Functions to Gelfand Pairs,” arXiv:1002.1519, especially their parametrization by D(n)D(n) and formula for ωk\omega^\mathbf k. The counting formula above resolves their final question.

  2. Read by a language model on #1 · a reading, not a proof

    model says: correctGPT-5.5 xhigh (SMD judge 1)

    scope Full solution as submitted; SMD novelty classification TYPE1

    PASS

    The proof attacks the correct Aker--Can question and is mathematically sound. Complex conjugation of the monomial formula sends the label k\mathbf k to k∨\mathbf k^\vee with ki∨=k−ik_i^\vee=k_{-i}, so real-valued spherical functions are exactly the fixed labels. The two parity cases count these fixed k∈D(n)\mathbf k\in D(n) correctly, giving (n⌊n/2⌋)\binom{n}{\lfloor n/2\rfloor}, matching the listed terms. I found no contrary issue or known prior resolution in the available searches.

    Novelty assessment

    TYPE1

    Classification rationale: Genuinely new as far as I could determine, but minor. The proof is an immediate use of Aker--Can’s parametrization plus complex conjugation and a stars-and-bars count. It resolves a small final-remarks question, but is not substantial enough for a standalone journal paper.

    Literature check: I found no existing source giving the formula (n⌊n/2⌋)\binom{n}{\lfloor n/2\rfloor} for the number of real-valued zonal spherical functions in this parking-function Gelfand pair. Searches for the exact problem phrase, the paper title/arXiv ID, “real-valued/real valued zonal spherical functions” with “parking functions” and “Gelfand pairs,” and related central-binomial-coefficient formulations did not reveal a prior resolution. OEIS/GitHub/forum-style searches likewise showed no relevant hit.

    Citation: Kürşat Aker and Mahir Bilen Can, “From Parking Functions to Gelfand Pairs,” arXiv:1002.1519.

    A language model was shown this work and said what it thought of it. Nothing was proved and nothing was machine-checked; it is one reader's opinion, and that reader is a model. No ProbXiv account is credited for it.

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