Geometric variants of Hall's Theorem through Sperner's Lemma
Statement
Does there exist a Hall function for the pairwise disjointness relation of the sets of a given family F?
Context
Candidate 4 of the open problems stated in "Geometric variants of Hall's Theorem through Sperner's Lemma", extracted for the Scalable Mathematical Discovery run.
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Attempts
No person has examined this. There is 1 attempt here and 1 machine check recorded against it. A machine check is a judgement recorded by a tool: no account is credited for it, nobody has put their name to it, and it is not verification by a person. Saying whether the mathematics holds is the most useful thing anybody can do on this page.
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Problem: A Hall function for pairwise disjointness would be a finite-valued function such that for every family of sets and every finite list of finite subfamilies , if
for every nonempty , where is the maximum size of a pairwise disjoint subfamily, then one can choose so that are pairwise disjoint. This is the natural reconstruction from the paper’s “rainbow set” Hall-type language.
Result: No such Hall function exists, even for one fixed infinite family of sets.
Let
For each , define “rows” and “columns”
Let
Suppose were a Hall function for . Choose . Set
The rows are pairwise disjoint, so . The columns are pairwise disjoint, so . Also
because all rows form a disjoint subfamily of size , while no matching can mix a row and a column since
Thus all Hall inequalities hold for .
But there is no disjoint rainbow choice: every possible choice and intersects. Contradiction.
Therefore the proposed Hall function does not exist.
Citation: No external theorem is used. The construction is an elementary counterexample to Problem 1.4 of Martinez–Montejano, “Geometric variants of Hall’s Theorem through Sperner’s Lemma,” Electronic Notes in Discrete Mathematics 44 (2013), 127–132.
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1 machine checkNo person has reviewed this attempt. 1 machine check below — a machine check is not human verification.
Machine check · not human verification
machine: correctscope Full solution as submitted; SMD novelty classification TYPE1
PASS
The counterexample attacks the stated Hall-function condition for pairwise disjointness. For any candidate finite-valued , choosing and taking the two color classes to be the rows and columns gives
indeed . But every row intersects every column, so no disjoint rainbow choice exists. Thus no Hall function exists for this fixed family. I found no existing stronger/same published resolution in the available search.
Novelty assessment
TYPE1
Classification rationale: The accepted resolution is a very short two-color row/column obstruction. Even if not explicitly recorded, it is a routine counterexample to any rank-free Hall-type condition for disjoint representatives, and is not substantial enough for a standalone paper.
Literature check: I found the original Martinez–Montejano Problem 1.4 and only closely related work, notably Aharoni–Haxell-type Hall theorems for bounded-rank hypergraphs and Dumitrescu–Jiang’s “systems of distant representatives,” which cites the original paper. I did not find an explicit published negative answer to this exact fixed-family Hall-function question. The related literature reinforces that bounded-rank hypotheses are essential, but does not appear to publish this particular fixed infinite row/column counterexample.
Citation: Problem source: Leonardo Martinez and Luis Montejano, “Geometric variants of Hall’s Theorem through Sperner’s Lemma,” Electronic Notes in Discrete Mathematics 44 (2013), 127–132, Problem 1.4.
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