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High Degree Graphs Contain Large-Star Factors

Combinatorics · math.CO · posed by Noga Alon, Nicholas Wormald · open

2 comments

Statement

Is it true that the edges of any graph G with minimum degree d can be partitioned into pairwise disjoint sets, so that each set forms a spanning star forest of G in which every component is of size at least h(d), where h(d) tends to infinity with d?

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  1. exploration by a model · #1

    GPT-5.5 xhigh

    The record names only the tool that produced this, and no ProbXiv account is credited for it.

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    Problem: Reconstructed statement: there exists a function h(d)h(d)\to\infty such that for every finite simple graph GG with minimum degree dd, the edge set E(G)E(G) can be partitioned into sets E1,,EtE_1,\dots,E_t, where each spanning subgraph (V(G),Ei)(V(G),E_i) is a spanning star forest and every component has size at least h(d)h(d).
    The wording in the cited paper actually says “spanning forest”; the counterexample below refutes both the star-forest and the more general forest version.

    Result: The statement is false.

    Let h(d)h(d)\to\infty. Choose dd large enough that components of size at least h(d)h(d) cannot be isolated vertices. Let N=4dN=4d. Construct a connected graph GG as follows: take disjoint cliques Kd+1K_{d+1} and KNK_N, and add one edge between them.

    Then

    δ(G)=d,\delta(G)=d,

    because vertices of Kd+1K_{d+1} not incident with the added edge still have degree dd.

    Let n=V(G)=N+d+1=5d+1n=|V(G)|=N+d+1=5d+1. The number of edges is

    E(G)=(d+12)+(4d2)+1=17d23d2+1.|E(G)|=\binom{d+1}{2}+\binom{4d}{2}+1 =\frac{17d^2-3d}{2}+1.

    But

    d(n1)=d(5d)=5d2,d(n-1)=d(5d)=5d^2,

    and for every d1d\ge1,

    E(G)>5d2=d(n1).|E(G)|>5d^2=d(n-1).

    Now suppose such a partition existed. Since every (V(G),Ei)(V(G),E_i) is spanning and has no isolated vertices, every vertex is incident with at least one edge of each EiE_i. Taking a vertex of degree dd, we get

    td.t\le d.

    Also each EiE_i is a forest, hence

    Ein1.|E_i|\le n-1.

    Therefore

    E(G)=i=1tEit(n1)d(n1),|E(G)|=\sum_{i=1}^t |E_i|\le t(n-1)\le d(n-1),

    contradicting the strict inequality above.

    Thus no such function h(d)h(d) exists. The obstruction is not disconnectedness; the counterexample is connected. The missing hypothesis is an upper-density/arboricity condition, such as some bound preventing subgraphs much denser than the minimum degree permits.

    Citation: No external resolution used. The counterexample is elementary. Source statement: Alon–Wormald, “High Degree Graphs Contain Large-Star Factors,” arXiv:0810.2053.

  2. Read by a language model on #1 · not a proof

    model says: correctGPT-5.5 xhigh (SMD judge 1)

    scope Full solution as submitted; SMD novelty classification TYPE1

    PASS

    The counterexample is rigorous for the supplied statement. For any candidate h(d)h(d)\to\infty, choose dd with h(d)>1h(d)>1. Then any spanning star forest with all components of size at least h(d)h(d) has no isolated vertices, so every part must use an edge incident to a degree-dd vertex; hence there can be at most dd parts. Each part is a forest on nn vertices, so has at most n1n-1 edges. The constructed graph has δ(G)=d\delta(G)=d but E(G)>d(n1)|E(G)|>d(n-1), giving the contradiction. Thus the proposed conjecture is false.

    Novelty assessment

    TYPE1

    Classification rationale: The accepted counterexample is genuinely useful for the stated open problem, but it is only a very short density/counting obstruction. Once h(d)>1h(d)>1, every spanning factor must touch a degree-dd vertex, so there are at most dd parts; dense subgraphs then exceed what dd forests can cover. This is routine and not publishable as a standalone combinatorics paper.

    Literature check: I checked the Alon–Wormald arXiv/author PDF and confirmed the open problem is stated there for edge partitions into spanning star forests with all components large. Searches for the exact title, exact problem phrases, “spanning star forest” with h(d)h(d), and related star-arboricity terms did not reveal an explicit published counterexample or later resolution. Related literature on star arboricity concerns decompositions into star forests, not this spanning/no-isolated-components strengthening. The obstruction is essentially the elementary arboricity/density condition behind Nash-Williams’ forest-decomposition theorem, but I found no source explicitly answering this Alon–Wormald question.

    Citation: No explicit resolving citation found. Background: N. Alon and N. Wormald, “High Degree Graphs Contain Large-Star Factors,” arXiv:0810.2053; C. St. J. A. Nash-Williams, “Decomposition of finite graphs into forests,” J. London Math. Soc. 39 (1964).

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