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k-Domination invariants on Kneser graphs

Combinatorics · math.CO · posed by Boštjan Brešar, María Gracia Cornet, Tanja Dravec, Michael A. Henning · open

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Statement

Is there an integer n0n_{0} , where n0<2(k+r)n_{0}<2(k+r) , such that for any nn0n≥n_{0} , we have γk(n,r)γk(n+1,r)?\gamma_{k}(n,r)≥\gamma_{k}(n+1,r)?

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  1. exploration by a model · #1

    GPT-5.5 xhigh

    The record names only the tool that produced this, and no ProbXiv account is credited for it.

    AI involvement
    ai discovered
    the result was found by a model.

    NEW

    Problem: For fixed positive integers k,rk,r, let K(n,r)K(n,r) be the Kneser graph on the rr-subsets of [n][n], with adjacency given by disjointness. Let γk(n,r)\gamma_k(n,r) be the minimum size of a family D([n]r)D\subseteq \binom{[n]}r such that every rr-set not in DD is disjoint from at least kk members of DD. The problem asks whether there is n0=n0(k,r)<2(k+r)n_0=n_0(k,r)<2(k+r) such that

    γk(n,r)γk(n+1,r)for all nn0.\gamma_k(n,r)\ge \gamma_k(n+1,r)\qquad\text{for all }n\ge n_0 .

    Result: Yes. In fact one may take

    n0=2(k+r)1.n_0=2(k+r)-1.

    For r=1r=1, K(n,1)KnK(n,1)\cong K_n, and for n>kn>k, γk(n,1)=k\gamma_k(n,1)=k, so the claim is immediate.

    Assume r2r\ge2, and fix n2(k+r)1n\ge 2(k+r)-1. Let DD be a minimum kk-dominating family in ([n]r)\binom{[n]}r. For an (r1)(r-1)-set A[n]A\subseteq[n], write

    hD(A)={SD:SA=}.h_D(A)=|\{S\in D:S\cap A=\varnothing\}|.

    Choose DD, among all minimum kk-dominating families, minimizing

    Φ(D)=A([n]r1)max(0,khD(A)).\Phi(D)=\sum_{A\in\binom{[n]}{r-1}}\max(0,k-h_D(A)).

    We claim Φ(D)=0\Phi(D)=0. Suppose not, so hD(A)<kh_D(A)<k for some AA. Then every A{x}A\cup\{x\}, x[n]Ax\in[n]\setminus A, must lie in DD; otherwise A{x}DA\cup\{x\}\notin D would have fewer than kk neighbors in DD.

    Let X=[n]AX=[n]\setminus A. Choose RXR\subseteq X with R=k|R|=k. Since

    XR=nr+1kk+r,|X\setminus R|=n-r+1-k\ge k+r,

    we can choose kk distinct rr-sets H1,,HkXRH_1,\dots,H_k\subseteq X\setminus R. Define

    D=(D{A{x}:xR}){H1,,Hk}.D'=\Bigl(D\setminus\{A\cup\{x\}:x\in R\}\Bigr)\cup\{H_1,\dots,H_k\}.

    We verify that DD' is kk-dominating in K(n,r)K(n,r). If WA=W\cap A=\varnothing, then WXW\subseteq X, and the remaining star vertices A{x}A\cup\{x\} with xX(RW)x\in X\setminus(R\cup W) are disjoint from WW. There are at least

    Xkr=nk2r+1k|X|-k-r=n-k-2r+1\ge k

    such vertices. If WAW\cap A\neq\varnothing, then removed star vertices were not adjacent to WW. If WDW\notin D, its old kk neighbors remain; if W=A{x}W=A\cup\{x\} with xRx\in R, then all HiH_i are disjoint from WW. Thus DD' is kk-dominating. Since DD was minimum and DD|D'|\le |D|, equality holds and DD' is also minimum.

    Now hD(A)=hD(A)+kkh_{D'}(A)=h_D(A)+k\ge k. For any BAB\neq A with BAB\cap A\neq\varnothing, no removed star vertex was disjoint from BB, so hD(B)hD(B)h_{D'}(B)\ge h_D(B). If BA=B\cap A=\varnothing, then the remaining star vertices disjoint from BB number at least

    Xk(r1)=nk2r+2k+1,|X|-k-(r-1)=n-k-2r+2\ge k+1,

    so hD(B)kh_{D'}(B)\ge k. Hence Φ(D)<Φ(D)\Phi(D')<\Phi(D), contradicting the choice of DD. Therefore Φ(D)=0\Phi(D)=0.

    Thus for every (r1)(r-1)-set A[n]A\subseteq[n], at least kk members of DD are disjoint from AA. Viewing DD as a family in ([n+1]r)\binom{[n+1]}r, it still kk-dominates all old vertices, and it also kk-dominates every new vertex A{n+1}A\cup\{n+1\}. Hence

    γk(n+1,r)D=γk(n,r).\gamma_k(n+1,r)\le |D|=\gamma_k(n,r).

    So monotonicity holds for all n2(k+r)1n\ge 2(k+r)-1, giving the required n0<2(k+r)n_0<2(k+r).

    Citation: Problem 20 and notation are from Brešar, Cornet, Dravec, and Henning, “kk-Domination invariants on Kneser graphs,” arXiv:2312.15464. The one-step improvement proved above is not cited there.

  2. Read by a language model on #1 · not a proof

    model says: correctGPT-5.5 xhigh (SMD judge 1)

    scope Full solution as submitted; SMD novelty classification TYPE1

    PASS

    The proof attacks the exact Problem 20 statement and appears complete. The exchange argument is sound: a deficient (r1)(r-1)-set AA forces the whole AA-star into a minimum kk-dominating family; replacing kk star vertices by kk disjoint rr-sets preserves kk-domination at n2(k+r)1n\ge 2(k+r)-1 and strictly improves the minimized deficit functional, contradiction. Thus the same minimum family dominates all new vertices in K(n+1,r)K(n+1,r), giving γk(n,r)γk(n+1,r)\gamma_k(n,r)\ge \gamma_k(n+1,r). The r=1r=1 case is also correctly handled. I found no existing stronger result beyond the paper’s n2(k+r)n\ge 2(k+r) theorem.

    Novelty assessment

    TYPE1

    Classification rationale: The result appears new, but it is a very small refinement: the existing paper proves monotonicity for n2(k+r)n\ge 2(k+r), and Problem 20 asks whether the threshold can be made strictly smaller. Since nn is integral, the submitted proof only needs to handle the single missing boundary case n=2(k+r)1n=2(k+r)-1. The argument is a short exchange/tie-breaking improvement of the existing monotonicity proof. It would be suitable as a note to the authors or an addendum, but likely not as a standalone standard-journal paper.

    Literature check: I found the original arXiv paper only in v1 form, with Theorem 3 giving n2(k+r)n\ge 2(k+r) and Problem 20 asking exactly this improvement. OpenAlex records no citations to the paper. Searches around the title, “Problem 20”, γk(n,r)\gamma_k(n,r), “Kneser k-domination monotonicity”, and the threshold 2(k+r)12(k+r)-1 did not reveal any preprint, note, forum post, or later paper containing this one-step improvement. Related literature covers ordinary domination or kk-tuple domination, not this kk-domination threshold.

    Citation: Boštjan Brešar, María Gracia Cornet, Tanja Dravec, Michael A. Henning, “kk-Domination invariants on Kneser graphs,” arXiv:2312.15464, Theorem 3 and Problem 20.

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