On a maximal distance between graphs
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Statement
If then Under which conditions the equality holds?
Context
Candidate 2 of the open problems stated in "On a maximal distance between graphs", extracted for the Scalable Mathematical Discovery run.
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NEW
Problem: Reconstructed statement: for finite simple undirected graphs, let be the class of graphs with vertices and edges. Let , where is the maximum number of edges in a common subgraph of and . The input has the evident typo ; it should be . For , characterize when
Result: Let denote the two-edge path and two disjoint edges. Then
if and only if
where subgraph means not necessarily induced.
Equivalently, using maximum degree and matching number ,
Thus, if , equality always holds. If , equality holds exactly when, after possibly interchanging , one graph is a matching and the other has no two disjoint edges; the latter is a star, or , together with isolated vertices.
Proof: Since , both graphs contain , so , giving . Equality holds exactly when , i.e. when the two graphs have no common two-edge subgraph. Every simple two-edge graph is isomorphic either to or to . Hence a common two-edge subgraph exists exactly when both graphs contain , or both contain . This proves the stated criterion. The reformulation follows because iff , and iff .
Verification audit: the reconstructed definition is exactly Šabo’s MCS distance for graphs with the same number of vertices; no extra hypotheses beyond finite simple graphs and were introduced; the conclusion is precisely the equality case in Problem 2.
Citation: Definitions and problem: Michal Šabo, “On a maximal distance between graphs,” Czechoslovak Mathematical Journal 41.2 (1991), 265–268. The characterization above is proved here.
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Machine check · not human verification
machine: correctscope Full solution as submitted; SMD novelty classification TYPE1
PASS
The proof attacks the correct equality case in Šabo’s Problem 2. For graphs with the same , the distance reduces to , where is the maximum number of edges in a common subgraph. Since , equality is exactly . The characterization by excluding common two-edge subgraphs is rigorous: the only non-isolated two-edge types are and , giving the stated degree/matching reformulation. No fatal gap or mismatch with the target statement is present.
Novelty assessment
TYPE1
Classification rationale: The accepted result is correct but essentially immediate from Šabo’s definition: equality is exactly the case where the maximum common subgraph has one edge, i.e. the two graphs have no common two-edge subgraph. Classifying two-edge simple graphs as or is a routine observation. This is not publishable as a standalone combinatorics result.
Literature check: I found no explicit later paper resolving Šabo’s Problem 2 in this exact form. Searches around Šabo’s title, maximal/common-subgraph distance, the bound , and the equality condition led only back to the original paper or to standard graph-theoretic facts. No stronger published characterization of this specific equality case was located.
Citation: Michal Šabo, “On a maximal distance between graphs,” Czechoslovak Mathematical Journal 41 (1991), no. 2, 265–268.
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