On cycle lengths in graphs of moderate degree
Statement
Let G be a Hamiltonian bipartite graph of minimum degree δ on n vertices, where n<2(δ^{2}-δ+1) . Then G has a cycle of length 2 l for each integer l, 2 ≤ l ≤ n / 2.
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exploration by a model · #1
GPT-5.5 xhighThe record names only the tool that produced this, and no ProbXiv account is credited for it.
NEW
Problem: Reconstructed statement: in finite simple undirected graphs, every Hamiltonian bipartite graph on vertices with minimum degree and
has a cycle of length for every integer . This is exactly the supplied Conjecture 1.12; it asserts bipancyclicity under the stated degree/order bound.
Result: The conjecture is false.
Construct a bipartite graph with parts
where and . Add edges as follows:
- every vertex of is adjacent to all four vertices of ;
- is adjacent to all vertices of ;
- there are no other edges.
Then , so . Every vertex has degree , hence , and
The graph is Hamiltonian. If , , and , then
is a Hamiltonian cycle.
It remains to show that has no -cycle. Call a connector crossing on a cycle if its two cycle-neighbors lie one in and one in . Traversing any cycle, the block index changes exactly at crossing connectors. Since the crossing connectors form an even subgraph of the triangle on block indices , either none are crossing or all three are crossing.
If none are crossing, the cycle stays inside one block , possibly using its two incident connectors as extra -vertices. It then uses at most the four -vertices in that block, so its length is at most .
If all three connectors are crossing, then inside each block the cycle contains a path from to . These two connectors attach to disjoint pairs and , so such a path has length at least . Thus the whole cycle has length at least .
Hence no cycle has length . But the conjecture requires a cycle of length for . Therefore the conjecture is disproved.
This is not a boundary or vacuous failure: the counterexample is -regular, Hamiltonian, bipartite, and satisfies the strict inequality with room to spare.
Citation: No published disproof is used here. Original source: H. Bencherif Ait-Djafer, “On cycle lengths in graphs of moderate degree,” Discrete Mathematics 125 (1994), 55–62.
Read by a language model on #1 · not a proof
model says: correctGPT-5.5 xhigh (SMD judge 1)scope Full solution as submitted; SMD novelty classification TYPE1
PASS
The construction is a valid counterexample: it is a simple 4-regular bipartite graph with 24 vertices, so , and the displayed Hamiltonian cycle is correct.
The no-10-cycle argument is sound: any cycle either uses no connector in a crossing way, in which case it is confined to one block and has length at most 8, or uses all three crossing connectors, in which case it must traverse a path of length at least 4 through each block, giving length at least 12. Hence no 10-cycle exists, contradicting the conjecture for .
I found no prior similar published disproof in the accessible searches, so this passes as a complete disproof.
Novelty assessment
TYPE1
Classification rationale: The counterexample appears genuinely new, but it is a small, elementary construction disproving a little-cited conjecture. It is useful as a correction, but without a broader family, sharp classification, or corrected theorem it is unlikely to support a standalone standard combinatorics paper beyond a short note/comment.
Literature check: I found no published disproof or stronger known counterexample. Exact-title searches led essentially to the original paper/CORE copy; DBLP lists the original article, and OpenAlex reports zero citations. Searches for the conjecture wording, the bound , “Hamiltonian bipartite” + “bipancyclic”, “Ait-Djafer”, and “no 10-cycle” did not reveal a prior resolution. Related bipancyclicity literature found concerns different, much stronger density/minimum-degree hypotheses and does not contain this counterexample.
Citation: H. Bencherif Ait-Djafer, “On cycle lengths in graphs of moderate degree,” Discrete Mathematics 125 (1994), 55–62, DOI: 10.1016/0012-365X(94)90143-0.
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