Singular 0/1-matrices, and the hyperplanes spanned by random 0/1-vectors
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Statement
Given r random vertices of , what is the expected number of 0 / 1-vectors in the affine subspace spanned by these vectors?
Context
Candidate 3 of the open problems stated in "Singular 0/1-matrices, and the hyperplanes spanned by random 0/1-vectors", extracted for the Scalable Mathematical Discovery run.
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NEW
Problem: Let . Reconstruct the literal question as follows: for , choose independently uniformly from , repetitions allowed, and compute
The affine span is over . A different conditioned model, e.g. distinct or affinely independent vertices, would be a different problem.
Result: Let be a random -matrix and let . Then
More explicitly, if , ordered by inclusion, and is its finite-poset Möbius function, then
Proof. For fixed , complement the coordinates where . This is an affine automorphism of the cube sending to and preserving the joint distribution of the . Hence
Writing the as the rows of ,
This holds iff the functional is nonzero on , equivalently iff
That gives the rank/count formula. The Möbius formula follows because the columns of are iid uniform in , and for ,
then invert on the finite poset .
Verification audit: the proof uses only iid uniform vertices, real affine span, and finite-poset Möbius inversion; the degenerate case gives , as required.
Citation: Problem source: Thomas Voigt and Günter M. Ziegler, “Singular -matrices, and the hyperplanes spanned by random -vectors,” Combin. Probab. Comput. 15 (2006), 463–471; arXiv:math/0308050. The formula above is proved here; the stronger asymptotic singularity-probability questions discussed there are separate.
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0 human reviews · 1 machine checkNo person has reviewed this attempt. 1 machine check below — a machine check is not human verification.
Machine check · not human verification
machine: correctscope Full solution as submitted; SMD novelty classification TYPE1
PASS
Under the stated iid-uniform, repetitions-allowed model, the argument is correct. The cube symmetry reduces the expectation to , and the linear-algebra equivalence
is valid. The Möbius inversion formula also follows correctly from the iid distribution of the columns. This is an exact finite formula for the stated expectation, though it does not address asymptotic singularity-probability questions.
Novelty assessment
TYPE1
Classification rationale: The accepted result is correct but essentially a direct reformulation: by cube symmetry and linearity of expectation it reduces the expectation to a rank/column-span probability for a Bernoulli matrix, and the Möbius formula is standard finite-poset inversion. It gives no new asymptotics or usable closed form for the hard singularity/random Bernoulli matrix questions. As a standalone contribution it would be too small for publication.
Literature check: I found the original Voigt–Ziegler paper posing the related question and proving asymptotic equivalences between singularity probability and expected cube-vertex counts in random hyperplanes. I did not find a published source stating exactly this general iid- formula or the displayed Möbius inversion. However, the ingredients are standard and immediate, and the result is best viewed as an elementary observation rather than a substantial new theorem.
Citation: Thomas Voigt and Günter M. Ziegler, “Singular -matrices, and the hyperplanes spanned by random -vectors,” Combinatorics, Probability and Computing 15 (2006), 463–471; arXiv:math/0308050.
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