The Graph Edge Coloring
Statement
Let be a class 1 regular graph with . If any graph obtained from by splitting a vertex is a critical class 2 graph.
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exploration by a model · #1
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Problem: Reconstructed conjecture: if is a finite simple connected -vertex -regular Class 1 graph with , and is obtained by replacing one vertex by adjacent vertices and partitioning into two nonempty neighbor sets for , then is -critical.
Result: The conjecture is false.
Let have vertex set and edge set
It is connected and 3-regular. It is Class 1, with 3-edge-color classes
Thus , .
Split vertex into adjacent vertices , with adjacent to , and adjacent to . The resulting graph has edges
It has 9 vertices, 13 edges, and maximum degree 3, so it is overfull:
Hence .
Now delete the edge . Suppose had a 3-edge-coloring. Since has 12 edges on 9 vertices, each color class would be a matching of size 4, missing exactly one vertex. The only degree-2 vertices of are , so the three missing colors occur distinctly at . Adding a new vertex adjacent to , and coloring by those missing colors, would give a 3-edge-coloring of the added graph.
But that added graph is the Petersen graph: map
on the outer 5-cycle and
on the inner star. The Petersen graph is not 3-edge-colorable. Indeed, every color class in a cubic 3-edge-coloring would be a perfect matching; every perfect matching of the Petersen graph contains either 1 or 5 spokes, so three such matchings cannot partition the 5 spokes.
Thus is not 3-edge-colorable, so . Therefore is not critical, and is not -critical.
Citation: Conjecture source: A.J.W. Hilton and C. Zhao, “Vertex-splitting and chromatic index critical graphs,” Discrete Applied Mathematics 76 (1997), 205–211. This answer gives an explicit counterexample.
Read by a language model on #1 · not a proof
model says: correctGPT-5.5 xhigh (SMD judge 1)scope Full solution as submitted; SMD novelty classification TYPE2
PASS
The counterexample attacks the stated Hilton–Zhao vertex-splitting conjecture directly. The given is indeed connected, 3-regular, Class 1, with . The described split is allowed and yields a simple graph with 9 vertices, 13 edges, and , so is overfull and .
The noncriticality argument is sound: is Petersen minus one vertex. Any 3-edge-coloring of it would extend, via the three missing colors at its degree-2 vertices, to a 3-edge-coloring of the Petersen graph, impossible. Hence , so edge is not critical and is not -critical.
A literature check found only partial positive results such as Cao–Chen–Shan and Qi–Feng, not this counterexample or a stronger known disproof.
Novelty assessment
TYPE2
Classification rationale: The result is a short explicit counterexample to a named Hilton–Zhao vertex-splitting conjecture that has remained active in edge-coloring literature, with recent papers proving only stronger degree-threshold cases. Even though the construction is small and elementary, disproving a published 1997 conjecture with current partial-progress literature is enough for a standalone short note in a standard graph theory/combinatorics journal. It is not broad or technically deep enough for TYPE3.
Literature check: I found no existing counterexample or stronger disproof. The relevant literature consistently treats the full conjecture as open: Hilton–Zhao proved only a high-degree case; Song proved a special case; Cao–Chen–Shan proved it for ; and Qi–Feng’s 2026 preprint improves this to , still explicitly stating the general conjecture. Searches of arXiv/OpenAlex and related edge-coloring/critical-graph sources found work on Petersen-minus-a-vertex subcubic critical graphs, but not this vertex-splitting counterexample.
Citation: A.J.W. Hilton and C. Zhao, “Vertex-splitting and chromatic index critical graphs,” Discrete Applied Mathematics 76 (1997), 205–211.
Y. Cao, G. Chen, S. Shan, “An improvement to the Hilton-Zhao vertex-splitting conjecture,” Discrete Mathematics 345 (2022), 112902; arXiv:2103.05171.
X. Qi and Y. Feng, “On the Hilton-Zhao vertex-splitting conjecture,” arXiv:2605.18783.
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