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Statement

independence_number(x)>= ceil(lovasz_theta(x))-girth(x)

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Source
  • AUTOMATED CONJECTURING VII: THE GRAPH BRAIN PROJECT & BIG MATHEMATICS
  • FAR
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  1. exploration by a model · #1

    GPT-5.5 xhigh

    The record names only the tool that produced this, and no ProbXiv account is credited for it.

    AI involvement
    ai discovered
    — the result was found by a model.

    NEW

    Problem: Reconstructed statement: for every finite simple graph GG,

    α(G)≥⌈ϑ(G)⌉−g(G),\alpha(G)\ge \lceil \vartheta(G)\rceil-g(G),

    where α\alpha is independence number, ϑ\vartheta is the usual Lovász theta number satisfying α(G)≤ϑ(G)\alpha(G)\le \vartheta(G), and g(G)g(G) is girth. The conjecture text lists exactly these graph invariants. The counterexample below is connected and has a triangle, so it is unaffected by common connectedness or girth-convention ambiguities.

    Result: The statement is false.

    Let HH be the disjoint union of 1313 copies of C5C_5, and let

    G=K1∨HG=K_1\vee H

    be the join of HH with one new universal vertex.

    Standard theta facts: ϑ(C5)=5\vartheta(C_5)=\sqrt5, ϑ\vartheta is additive on disjoint unions, and

    ϑ(A∨B)=max⁡{ϑ(A),ϑ(B)}.\vartheta(A\vee B)=\max\{\vartheta(A),\vartheta(B)\}.

    Hence

    ϑ(G)=ϑ(H)=135.\vartheta(G)=\vartheta(H)=13\sqrt5.

    Since 292<132⋅5<30229^2<13^2\cdot 5<30^2, we have

    ⌈ϑ(G)⌉=⌈135⌉=30.\lceil \vartheta(G)\rceil=\lceil 13\sqrt5\rceil=30.

    Also, each C5C_5 has independence number 22, so

    α(H)=26.\alpha(H)=26.

    The universal vertex cannot be used together with any vertex of HH, hence

    α(G)=26.\alpha(G)=26.

    Finally, GG contains a triangle: the universal vertex together with any edge of a C5C_5. Thus

    g(G)=3.g(G)=3.

    Therefore the conjectured inequality gives

    26=α(G)≥⌈ϑ(G)⌉−g(G)=30−3=27,26=\alpha(G)\ge \lceil\vartheta(G)\rceil-g(G)=30-3=27,

    which is false. So this connected 6666-vertex graph is a counterexample.

    Citation: The theta facts used above are classical; see L. Lovász, “On the Shannon capacity of a graph,” IEEE Trans. Inform. Theory 25 (1979), 1–7.

  2. Read by a language model on #1 · not a proof

    model says: correctGPT-5.5 xhigh (SMD judge 1)

    scope Full solution as submitted; SMD novelty classification KNOWN

    PASS

    The counterexample attacks the correct conjecture. For G=K1∨(13C5)G=K_1\vee(13C_5), the standard theta identities give ϑ(G)=135\vartheta(G)=13\sqrt5, so ⌈ϑ(G)⌉=30\lceil\vartheta(G)\rceil=30. Also α(G)=26\alpha(G)=26 and g(G)=3g(G)=3, hence the conjectured bound would require 26≥2726\ge 27, false. The graph is connected, and the cited theta facts are standard.

    Novelty assessment

    KNOWN

    Classification rationale: The accepted solution gives a counterexample, but the exact conjecture was already publicly resolved negatively. Thus the resolution is not new, even if the 66-vertex construction is a different certificate.

    Literature check: Searching the exact Graph Brain syntax and variants led to the project’s earlier issue #191, “Open Conjecture: alpha >= ceil(lovasz_theta) - girth.” In a comment dated Oct. 28, 2017, user a234 states: “The Paley graph of order 101 is a counterexample.” The issue is now closed.

    Citation: math1um/objects-invariants-properties, Issue #191, “Open Conjecture: alpha >= ceil(lovasz_theta) - girth,” comment by a234, Oct. 28, 2017. https://github.com/math1um/objects-invariants-properties/issues/191#issuecomment-340132963

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