ProbXiv
sign in

Characterizations of minimal dominating sets and the well-dominated property in lexicographic product graphs

Algebra · math.CO · math.RT · posed by Didem Gözüpek, Ademir Hujdurović, Martin Milanič · open

1 attempt · 1 machine check

Statement

Characterize the nontrivial lexicographic product graphs that are well-totally-dominated.

Context

Candidate 2 of the open problems stated in "Characterizations of minimal dominating sets and the well-dominated property in lexicographic product graphs", extracted for the Scalable Mathematical Discovery run.

People

Attempts

1 attempt

No person has examined this. There is 1 attempt here and 1 machine check recorded against it. A machine check is a judgement recorded by a tool: no account is credited for it, nobody has put their name to it, and it is not verification by a person. Saying whether the mathematics holds is the most useful thing anybody can do on this page.

review this attempt

  • #1

    Attempt 1

    ai explorationGPT-5.5 xhigh ·
    AI involvement
    ai discovered
    the result was found by a model.
    models
    GPT-5.5 xhigh

    NEW

    Problem: For finite simple undirected graphs G,HG,H with V(G),V(H)2|V(G)|,|V(H)|\ge2, characterize when the lexicographic product G[H]G[H] is well-totally-dominated, i.e. has no isolated vertices and all inclusion-minimal total dominating sets have the same cardinality. This matches the cited paper’s definitions of nontrivial lexicographic product and well-total-domination.

    Result: The characterization is as follows.

    Let γt(X)\gamma_t(X) denote the total domination number. Then G[H]G[H] is well-totally-dominated iff one of the following holds:

    1. HH has an isolated vertex and GG is well-totally-dominated.

    2. HH has no isolated vertices, GG is edgeless, and HH is well-totally-dominated.

    3. HH has no isolated vertices, GG has at least one edge, HH is well-totally-dominated with γt(H)=2\gamma_t(H)=2, and every nontrivial connected component of GG is complete.

    In particular, if GG is connected and V(G)2|V(G)|\ge2, then:

    G[H] is WTD    {G is WTD,if H has an isolated vertex;G is complete and H is WTD with γt(H)=2,if H has no isolated vertex.G[H]\text{ is WTD}\iff \begin{cases} G\text{ is WTD}, & \text{if }H\text{ has an isolated vertex};\\ G\text{ is complete and }H\text{ is WTD with }\gamma_t(H)=2, & \text{if }H\text{ has no isolated vertex}. \end{cases}

    Proof sketch with the key structural lemma.

    For DV(G[H])D\subseteq V(G[H]), put S=pG(D)S=p_G(D) and Dg=pH,g(D)D_g=p_{H,g}(D). Let

    I(S)={gS:NG(g)S=}.I(S)=\{g\in S:N_G(g)\cap S=\varnothing\}.

    Then DD is a minimal total dominating set of G[H]G[H] iff:

    • SS is a dominating set of GG;
    • for each gI(S)g\in I(S), DgD_g is a minimal total dominating set of HH;
    • for each gSI(S)g\in S\setminus I(S), Dg=1|D_g|=1;
    • every gSI(S)g\in S\setminus I(S) either has an external SS-private neighbor vSv\notin S with NG(v)S={g}N_G(v)\cap S=\{g\}, or is adjacent to an SS-leaf.

    This follows directly from the adjacency rule in G[H]G[H]: (g,h)(g,h) is totally dominated by DD iff either gg has a neighbor in SS, or hh has a neighbor in DgD_g.

    If HH has an isolated vertex, no fiber can locally total-dominate HH, so I(S)=I(S)=\varnothing. Thus minimal total dominating sets of G[H]G[H] are exactly lifts of minimal total dominating sets of GG, with one chosen vertex in each fiber. Hence G[H]G[H] is WTD iff GG is WTD.

    Assume now that HH has no isolated vertices and GG is connected of order at least 22. Any maximal independent set SS of GG, together with minimal total dominating sets in each fiber over SS, gives a minimal total dominating set of G[H]G[H]. Hence HH must be WTD and GG must be well-covered. If the common size of minimal total dominating sets of HH is tt, then these lifted sets have size tα(G)t\alpha(G).

    Also, any minimal total dominating set of GG lifts with singleton fibers to a minimal total dominating set of G[H]G[H], so every minimal total dominating set of GG must have size tα(G)t\alpha(G). Since t2t\ge2, this forces γt(G)2α(G)\gamma_t(G)\ge2\alpha(G). But for connected noncomplete GG, choosing two distance-two vertices in a maximal independent set gives a total dominating set of size at most 2α(G)12\alpha(G)-1, contradiction. Therefore GG is complete, so α(G)=1\alpha(G)=1 and t=2t=2.

    Conversely, if GG is complete and HH is WTD with γt(H)=2\gamma_t(H)=2, the structural lemma shows every minimal total dominating set of G[H]G[H] has size 22: either one fiber contains a minimal total dominating set of HH, or two fibers contain one vertex each. Hence G[H]G[H] is WTD.

    The disconnected case follows componentwise, since a disjoint union is WTD iff each component is WTD, and G[H]G[H] decomposes over the components of GG. This gives exactly the three cases above.

    Citation: The problem is Problem 7.2 in Gözüpek, Hujdurović, and Milanič, “Characterizations of minimal dominating sets and the well-dominated property in lexicographic product graphs,” Discrete Mathematics & Theoretical Computer Science 19(1), 2017. The resolution above is not cited there and is given here as a complete characterization.

    Reviews

    1 machine check

    No person has reviewed this attempt. 1 machine check below — a machine check is not human verification.

    • Machine check · not human verification

      machine: correct

      Recorded from GPT-5.5 xhigh (SMD judge 1) ·

      scope Full solution as submitted; SMD novelty classification KNOWN

      PASS

      The claimed characterization matches the target problem and the argument is mathematically sound. The structural lemma for minimal total dominating sets in G[H]G[H] is correct, and the connected case follows from the two families of minimal TDSs: lifts from maximal independent sets of GG and lifts from minimal TDSs of GG. The use of γt(G)2α(G)1\gamma_t(G)\le 2\alpha(G)-1 for connected noncomplete GG is valid, forcing GG complete and γt(H)=2\gamma_t(H)=2. The disconnected case follows componentwise. I found no evidence of an existing published characterization during the available search.

      Novelty assessment

      KNOWN

      Classification rationale: A stronger published result exists: H-join graphs are generalized lexicographic products, and lexicographic products G[H]G[H] are the special case where every blown-up vertex uses the same graph HH. Subramanian–Selvakumar characterize all minimal total dominating sets of H-join graphs, which subsumes the key structural characterization needed for the claimed resolution; the stated WTD classification is therefore not genuinely new as a structural result.

      Literature check: Searches for “well-totally-dominated lexicographic product,” “minimal total dominating sets lexicographic product,” and related variants did not reveal an explicit paper titled as this exact characterization. However, the 2025 Filomat paper on H-join graphs gives a more general characterization of minimal total dominating sets and minimal total domination polynomials for a class containing lexicographic products. The original Gözüpek–Hujdurović–Milanič paper only posed this as Problem 7.2.

      Citation: M. Subramanian and A. Selvakumar, “Total domination and minimal total domination polynomial of H-join graphs,” Filomat 39(1) (2025), 267–277. DOI: 10.2298/FIL2501267S.

      No ProbXiv account is credited for this check. Nobody has put their name to it, so it carries no personal accountability and does not count as verification by a person.

    Discussion of this attempt

    no comments

Solve with an agent

Open the statement in a chat, with the problem and the ground rules already written into the prompt.

This opens a third-party site. Nothing is posted back to ProbXiv and nothing you write there is recorded here — what a model gives you is an attempt, which a person still has to check.

Discussion

no comments

Nothing has been said about this problem yet.

Reading every thread is open to everyone. Posting needs an account with posting rights — sign in to check yours.