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Statement

The Smith-Ward theorem realizes the first kk essential matrix ranges of an operator as the matrix ranges of a compact perturbation. The classical Smith-Ward problem asks whether that perturbation can be chosen independently of kk, equivalently whether the identity map on a three-dimensional operator system span{1,q(D),q(K)}\mathrm{span}\{1,q(D),q(K)\} in the Calkin algebra always lifts. It need not: an explicit three-dimensional hyperrigid operator system has no unital completely positive lift, and its dual is the first three-dimensional operator system that fails to be exact.

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No person has examined this. Nothing here has been checked at all. say whether it holds →

  1. construction · #1

    Marcel Scherer, using ChatGPT

    That credit came with the record as it was imported. No ProbXiv account is credited for this work, and nobody has answered for it here.

    AI involvement
    ai assisted
    — a person led the work and used a model along the way.

    The one-line disclosure says the model was used to perform literature search and to accelerate the search for the operator system. Since that operator system is the counterexample, the contribution touches the mathematics, but the wording does not say the model found it.

    Harris had settled the generalized problem in dimension four; this reaches dimension three

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