Clustering of Consecutive Numbers in Permutations Avoiding a Pattern and in Separable Permutations
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Statement
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Context
Candidate 2 of the open problems stated in "Clustering of Consecutive Numbers in Permutations Avoiding a Pattern and in Separable Permutations", extracted for the Scalable Mathematical Discovery run.
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NEW
Problem: Reconstructed conjecture: for every pattern and every admissible sequence with for each fixed and all large ,
where is the event that the value interval occupies some consecutive positions in the permutation.
Result: The conjecture is false as stated.
Take and . A permutation avoids iff it is strictly decreasing, so
In this unique permutation, for every fixed and every , the values occur in the last positions:
Hence occurs with probability under . Therefore
for every , and consequently
Thus the literal conjecture fails. The same defect occurs for . A natural minimal repair would be to exclude the two length- monotone patterns, i.e. require .
Citation: No external disproof is needed; the counterexample follows immediately from the definitions in Pinsky, “Clustering of consecutive numbers in permutations avoiding a pattern and in separable permutations,” arXiv:2109.09370.
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0 human reviews · 1 machine checkNo person has reviewed this attempt. 1 machine check below — a machine check is not human verification.
Machine check · not human verification
machine: correctscope Full solution as submitted; SMD novelty classification KNOWN
PASS
The proposed disproof is valid for the literal conjecture supplied. Since , the class consists only of the decreasing permutation. For , the set always occupies the last consecutive positions, so the probability is for every fixed and all large . Thus the stated limit is , not . This rigorously disproves the conjecture as written.
Novelty assessment
KNOWN
Classification rationale: The counterexample is valid, but it is not genuinely new: Pinsky’s own paper contains a stronger general lower bound that already covers and . Since , Corollary 1(iii) forces the relevant limiting probabilities to be , contradicting the later conjecture as stated.
Literature check: The current arXiv version of Pinsky, arXiv:2109.09370, states the conjecture with . In the same paper, Theorem 1(iii) and Corollary 1(iii) apply to patterns not containing tightly at least one of , which includes and . Thus the paper itself already contains the stronger ingredient implying this length-two counterexample. Follow-up arXiv:2211.12090 concerns length-three/simple-pattern cases and is not needed.
Citation: Ross G. Pinsky, “Clustering of consecutive numbers in permutations avoiding a pattern and in separable permutations,” arXiv:2109.09370, Theorem 1(iii), Corollary 1(iii), and the Conjecture in §1.
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