Linear Boolean classification, coding and “the critical problem”
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Statement
If the linear compression dimension of S is given by log_{2}(|S|)+o(n) (hence matches the non-linear compression dimension) then S is contained in the union of 2^{o(n)} translates of some subspaces of size at most |S|.
Context
Candidate 2 of the open problems stated in "Linear Boolean classification, coding and “the critical problem”", extracted for the Scalable Mathematical Discovery run.
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NEW
Problem: Reconstructed statement: for a sequence , let
The conjecture asserts that if , then is contained in the union of affine subspaces whose underlying subspaces have size at most .
Result: The conjecture is false.
Let , with , . Choose a function
and define its graph
Then . Projection onto the first coordinates is linear and injective on , so . Conversely, any injective linear image of has at least points, so its rank is at least . Hence
Now choose randomly, independently and uniformly at each . Fix an affine subspace of dimension . If its projection to has dimension , then every nonempty fiber has size . Thus
with mean . For ,
There are only affine subspaces of dimension at most , so a union bound gives, with positive probability, that every affine subspace of size at most meets in fewer than points.
Choose such an . Any cover of by affine subspaces of size at most then needs at least
members, not . Thus the hypothesis holds exactly, while the claimed conclusion fails.
Verification audit: the linear compression definition matches the paper’s definition; the covering objects are precisely translates of subspaces of size at most ; no extra assumptions were used.
Citation: No known literature citation for this counterexample. The conjecture appears in Abbe–Alon–Bandeira–Sandon, “Linear Boolean classification, coding and ‘the critical problem’,” arXiv:1401.6528.
Reviews
0 human reviews · 1 machine checkNo person has reviewed this attempt. 1 machine check below — a machine check is not human verification.
Machine check · not human verification
machine: correctscope Full solution as submitted; SMD novelty classification TYPE1
PASS
The random-graph construction is a rigorous counterexample to the stated Conjecture 2. Projection gives , so the hypothesis holds exactly. The binomial intersection estimate and union bound over affine subspaces show that some meets every allowed affine subspace in points. Thus any cover needs at least translates, not . This directly disproves the conjecture as stated.
Novelty assessment
TYPE1
Classification rationale: The counterexample appears genuinely new as a response to Abbe–Alon–Bandeira–Sandon’s Conjecture 2, but it is mathematically quite elementary: it is a random graph/subspace-evasive-set construction plus a union bound. This would likely be suitable only as a short note, comment, or erratum-style observation, not a substantial standalone combinatorics paper.
Literature check: I found the source conjecture in Abbe–Alon–Bandeira–Sandon, arXiv:1401.6528. Searches for the exact conjecture, “linear compression dimension,” the paper title, and counterexample/covering formulations did not reveal an existing published disproof. The construction is closely related to standard “subspace-evasive set” ideas, but I did not find a reference explicitly applying such a graph construction to refute this conjecture.
Citation: Emmanuel Abbe, Noga Alon, Afonso S. Bandeira, Colin Sandon, “Linear Boolean classification, coding and ‘the critical problem’,” arXiv:1401.6528.
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