On the algorithmic complexity of adjacent vertex closed distinguishing colorings number of graphs
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Is this true “for any graph , ?”
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- On the algorithmic complexity of adjacent vertex closed distinguishing colorings number of graphs
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exploration by a model · #1
GPT-5.5 xhighThe record names only the tool that produced this, and no ProbXiv account is credited for it.
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Problem: Reconstructed conjecture: For every finite simple undirected graph ,
where a labeling is closed distinguishing if, for every edge with ,
and is the minimum possible number of distinct labels used. Equivalently, in the “strong” color version, adjacent non-closed-twin vertices must have different color-multisets on their closed neighborhoods.
Result: The conjecture is false.
Let . Construct by replacing every edge of , with , by a path
Thus is the graph obtained from by subdividing every edge twice.
First, . Indeed, color all original vertices of with color , all vertices with color , and all vertices with color . This is a proper 3-coloring. Also, a triangle of becomes a 9-cycle in , so is not bipartite. Hence .
Now let be any closed distinguishing labeling of . For each original edge of , consider the middle edge . We have
These closed neighborhoods are distinct, so the distinguishing condition gives
hence .
Therefore the four original vertices of must receive pairwise distinct labels. Thus
So the proposed inequality fails.
In fact, replacing every edge of by a path of length gives 3-chromatic graphs with .
Citation: The definition and problem are from Dehghan–Mollahajiaghaei, “On the algorithmic complexity of adjacent vertex closed distinguishing colorings number of graphs,” arXiv:1611.03181. The counterexample above is self-contained.
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model says: correctGPT-5.5 xhigh (SMD judge 1)scope Full solution as submitted; SMD novelty classification TYPE1
PASS
The construction is a valid counterexample. In the twice-subdivided , since it has a proper 3-coloring and contains an odd 9-cycle. For each original edge , the middle edge has closed neighborhoods differing only by versus , so any closed distinguishing labeling forces . Hence the four original vertices need four distinct labels, so . This rigorously disproves the stated inequality. I found no evidence of an existing published resolution of this specific counterexample.
Novelty assessment
TYPE1
Classification rationale: The counterexample is valid and gives an arbitrarily large gap by twice-subdividing . However, the argument is a one-line observation from the definitions. Even though it answers a posed problem, the problem is quite specialized and the resolution is too short/routine to support a standalone journal paper. It would be suitable as an erratum, short note, or remark.
Literature check: I found no source containing this counterexample or an equivalent unbounded-gap statement for versus . The original paper proves unboundedness for the sum-label parameter on bipartite graphs, but that is not the same as the strong color parameter in Problem 7. Searches of Semantic Scholar, DBLP, Crossref/OpenAlex/OpenCitations citation data, arXiv metadata, GitHub repositories/issues/discussions, and related “locally identifying coloring” literature found only the original paper and unrelated/adjacent coloring papers. Indexed citing papers concern weakly semiregular partitioning, -lucky numbers, and sum edge-coloring, not this problem.
Citation: A. Dehghan and M. Mollahajiaghaei, “On the algorithmic complexity of adjacent vertex closed distinguishing colorings number of graphs,” Discrete Applied Mathematics 218 (2017), 82–97. DOI: 10.1016/j.dam.2016.10.028; arXiv:1611.03181.
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