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A monic prime PP of Fq[T]\mathbb{F}_q[T] is a cc-Wieferich prime if ρP(1)≡1 mod P2\rho_P(1) \equiv 1 \bmod P^2 for the Carlitz module ρ\rho. On limited data and proofs in degrees 22 and 33, Thakur suggested in 2015 that in odd characteristic every cc-Wieferich prime has degree divisible by pp. It is false: an explicit irreducible cc-Wieferich prime has degree not divisible by pp, and the resulting common factor has a closed form.

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  1. construction · #1

    Claude Opus 4.8, with David Niedbala Giraudin

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    AI involvement
    ai discovered
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    The methodology section is the most explicit division of labour in this batch. The author is an independent researcher with no formal mathematical training. He set the research direction and the criteria for which problems to pursue and contributed a structural, visual reading of the objects; the model proposed problems meeting those criteria and supplied the mathematical domain knowledge, the formalization, the drafting, and the design and execution of all computations, under his direction. The strategy emerged from the dialogue. Lacking the training to verify the mathematics directly, the author relied on exact computational checks reproduced across independent systems.

  2. Recorded elsewhere on #1 · not checked here

    recorded: correctVibeMathed site check

    scope Reproduction by the VibeMathed site

    Independently reproduced. We recomputed the claim from the definitions in arXiv:2607.15305, from scratch and with no computer-algebra dependency, so the check shares no code with the author's appendix. Confirmed: x3−8x2−4x−11x^3-8x^2-4x-11 is irreducible over F19\mathbb{F}_{19}, so F193\mathbb{F}_{19^3} is a field; PP is monic of degree 55, irreducible over F193\mathbb{F}_{19^3}, and genuinely uses the cubic extension; and ρP(1)≡1 mod P2\rho_P(1) \equiv 1 \bmod P^2, which is the definition of a cc-Wieferich prime, computed through the Carlitz recursion inside Fq[T]/(P2)\mathbb{F}_q[T]/(P^2). The Bamunoba-Bergstrom criterion the paper cites, M5(θ)=0M_5(\theta) = 0, was computed by a separate route and agrees. We also confirmed that μ(X)\mu(X) divides X+Xq+⋯+Xq4X + X^q + \cdots + X^{q^4}, which is what makes G=μ(Tq−T)G = \mu(T^q - T) divide [5][5]. Since 19∤519 \nmid 5, the counterexample stands. This matters more than usual here because the author states he cannot verify the mathematics directly. arXiv preprint (v2), not peer-reviewed.

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