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Suppose now that b≤a<sb \le a < s, and m≫n1+s−1m \gg n^{1+s-1}. Then

satex(n,K1,s:m,Ka,b)=(1+o(1))min⁡{N(Ka,b,Kq∗),N(Ka,b,Kr∗‾)},\text{satex}(n, K_{1,s} : m, K_{a,b}) = (1 + o(1)) \min\{\mathcal{N}(K_{a,b}, K_q^*), \mathcal{N}(K_{a,b}, \overline{K_r^*})\},

where q=min⁡{t∈Z:N(K1,s,Kt)≥m}q = \min\{t \in \mathbb{Z} : \mathcal{N}(K_{1,s}, K_t) \ge m\} and r=min⁡{t∈Z:N(K1,s,Kt‾)>m}r = \min\{t \in \mathbb{Z} : \mathcal{N}(K_{1,s}, \overline{K_t}) > m\}.

Record

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  • Unified approach to the generalized Turán problem and supersaturation
  • FAR
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No person has examined this. Everything below was judged by machines. say whether it holds →

  1. exploration by a model · #1

    GPT-5.5 xhigh

    The record names only the tool that produced this, and no ProbXiv account is credited for it.

    AI involvement
    ai discovered
    — the result was found by a model.

    NEW

    Problem: Reconstructed statement: in finite simple nn-vertex graphs, satex⁡(n,F:m,G)\operatorname{satex}(n,F:m,G) is the minimum number of copies of GG among graphs containing at least mm copies of FF. For fixed integers 1≤b≤a<s1\le b\le a<s and m(n)≫nsm(n)\gg n^s, Conjecture 4.4 asserts

    satex⁡(n,K1,s:m,Ka,b)=(1+o(1))min⁡{N(Ka,b,Kq∗),N(Ka,b,Kr∗‾)},\operatorname{satex}(n,K_{1,s}:m,K_{a,b}) =(1+o(1))\min\{\mathcal N(K_{a,b},K_q^*),\mathcal N(K_{a,b},\overline{K_r^*})\},

    with qq and rr as in the prompt. Here Kt∗(n)K_t^*(n) is the nn-vertex graph consisting of a KtK_t plus isolated vertices, and Kt∗‾\overline{K_t^*} is its complement.

    Result: The conjecture is false. Take

    s=4,a=b=3.s=4,\qquad a=b=3.

    Let

    Cn=N(K1,4,Kn),Dn=N(K3,3,Kn).C_n=\mathcal N(K_{1,4},K_n),\qquad D_n=\mathcal N(K_{3,3},K_n).

    Choose small fixed ε>0\varepsilon>0, put h=1−εh=1-\varepsilon,

    β=h+(1−h)h4,α=β+ε3,\beta=h+(1-h)h^4,\qquad \alpha=\beta+\varepsilon^3,

    and set mn=⌊βCn⌋m_n=\lfloor \beta C_n\rfloor. Then mn=Θ(n5)m_n=\Theta(n^5), so mn≫n4m_n\gg n^4.

    For the clique term, q/n→β1/5q/n\to \beta^{1/5}, hence

    N(K3,3,Kq∗)=(β6/5+o(1))Dn.\mathcal N(K_{3,3},K_q^*)=(\beta^{6/5}+o(1))D_n.

    With the printed “minimum” definition of rr, the quasi-star term is asymptotically at least DnD_n, so the conjectured right-hand side is

    (β6/5+o(1))Dn.(\beta^{6/5}+o(1))D_n.

    Now take Gn∼G(n,p)G_n\sim G(n,p) with p=α1/4p=\alpha^{1/4}. Standard fixed-subgraph concentration gives, with positive probability,

    N(K1,4,Gn)=(α+o(1))Cn≥mn\mathcal N(K_{1,4},G_n)=(\alpha+o(1))C_n\ge m_n

    and

    N(K3,3,Gn)=(p9+o(1))Dn=(α9/4+o(1))Dn.\mathcal N(K_{3,3},G_n)=(p^9+o(1))D_n=(\alpha^{9/4}+o(1))D_n.

    Taylor expansion at ε=0\varepsilon=0 gives

    α9/4<β6/5\alpha^{9/4}<\beta^{6/5}

    for all sufficiently small ε>0\varepsilon>0. Thus

    satex⁡(n,K1,4:mn,K3,3)≤(α9/4+o(1))Dn<(β6/5+o(1))Dn,\operatorname{satex}(n,K_{1,4}:m_n,K_{3,3}) \le (\alpha^{9/4}+o(1))D_n <(\beta^{6/5}+o(1))D_n,

    contradicting the conjectured asymptotic value.

    This is not merely caused by the likely typo in the definition of rr: if rr is repaired in the natural way so that Kr∗‾\overline{K_r^*} is the quasi-star with βCn+o(n5)\beta C_n+o(n^5) copies of K1,4K_{1,4}, then its K3,3K_{3,3}-count is

    (2h3−h6+o(1))Dn,(2h^3-h^6+o(1))D_n,

    while

    α9/4=1−9ε2+634ε3+O(ε4)<1−9ε2+18ε3+O(ε4)=2h3−h6.\alpha^{9/4}=1-9\varepsilon^2+\tfrac{63}{4}\varepsilon^3+O(\varepsilon^4) <1-9\varepsilon^2+18\varepsilon^3+O(\varepsilon^4) =2h^3-h^6.

    So the same random graph also beats the natural repaired quasi-star/clique prediction.

    Citation: No prior resolution is used here. The conjecture is from Gerbner–Nagy–Vizer, “Unified approach to the generalized Turán problem and supersaturation,” arXiv:2008.12093, Conjecture 4.4.

  2. Read by a language model on #1 · not a proof

    model says: correctGPT-5.5 xhigh (SMD judge 1)

    scope Full solution as submitted; SMD novelty classification TYPE1

    PASS

    The proposed counterexample is mathematically valid. For s=4s=4, a=b=3a=b=3, the chosen mn=⌊βN(K1,4,Kn)⌋m_n=\lfloor \beta \mathcal N(K_{1,4},K_n)\rfloor satisfies the conjecture’s growth condition. The asymptotics for the clique term give β6/5Dn\beta^{6/5}D_n, while a dense random graph G(n,p)G(n,p) with p=α1/4p=\alpha^{1/4} has at least mnm_n copies of K1,4K_{1,4} and only (α9/4+o(1))Dn(\alpha^{9/4}+o(1))D_n copies of K3,3K_{3,3}. The Taylor comparison α9/4<β6/5\alpha^{9/4}<\beta^{6/5} for small fixed ε>0\varepsilon>0 is correct, yielding a strict asymptotic contradiction.

    The concentration claims are standard for fixed subgraph counts in G(n,p)G(n,p), and the argument also addresses the natural corrected quasi-star interpretation of rr. I did not find a prior resolution of this specific conjecture in the available literature search.

    Novelty assessment

    TYPE1

    Classification rationale: Genuinely new as far as I could determine, but minor: it is a simple explicit counterexample to one conjecture, using standard dense random graph subgraph-count asymptotics/concentration. It does not determine the correct supersaturation-extremal value or introduce a new method. Best suited as an erratum/remark or part of a broader paper, not a standalone journal article.

    Literature check: I found no prior resolution of Gerbner–Nagy–Vizer Conjecture 4.4. ArXiv searches for “satex,” “supersaturation-extremal function,” the relevant K1,4K_{1,4}/K3,3K_{3,3} terms, and related star/complete-bipartite formulations did not reveal a later paper proving or disproving this conjecture. The original paper notes related results for a=b=1a=b=1 and cites Day–Sarkar’s counterexamples to Nagy’s different edge-density quasi-star/quasi-clique conjecture; those are related in spirit but do not imply this counterexample.

    Citation: D. Gerbner, Z. L. Nagy, M. Vizer, “Unified approach to the generalized Turán problem and supersaturation,” arXiv:2008.12093, Conjecture 4.4. Related but not resolving it: A. N. Day, A. Sarkar, “On a Conjecture of Nagy on Extremal Densities,” arXiv:1910.13465.

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