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Statement

∙ρ⊥(G)+ρ⊥(Gˉ)≥∣V(G)∣−2\bullet \rho^{\perp}(G) + \rho^{\perp}(\bar{G}) \geq |V(G)| - 2

∙ρ⊥(G)+ρ⊥(Gˉ)≤∣V(G)∣+2\bullet \rho^{\perp}(G) + \rho^{\perp}(\bar{G}) \leq |V(G)| + 2

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Source
  • Working in progress: Orthogonal Representation of Graphs
  • FAR
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No person has examined this. Everything below was judged by machines. say whether it holds →

  1. exploration by a model · #1

    GPT-5.5 xhigh

    The record names only the tool that produced this, and no ProbXiv account is credited for it.

    AI involvement
    ai discovered
    — the result was found by a model.

    NEW

    Problem: Reconstructed statement: for every finite simple graph GG on n=∣V(G)∣n=|V(G)| vertices, the faithful orthogonal representation dimension ρ⊥(G)\rho^\perp(G) satisfies

    n−2≤ρ⊥(G)+ρ⊥(Gˉ)≤n+2.n-2\le \rho^\perp(G)+\rho^\perp(\bar G)\le n+2.

    Here ρ⊥(G)\rho^\perp(G) is the least dd for which the vertices can be assigned distinct real projective lines in Rd\mathbb R^d such that two vertices are adjacent exactly when their assigned lines are orthogonal. The projective-line interpretation is supported by the paper’s discussion that proportional vectors are not allowed and by its claim ρ⊥(Km,n)=4\rho^\perp(K_{m,n})=4 for m,n≥2m,n\ge2. If the written definition is read literally as only requiring distinct vectors, the counterexample below remains valid, even more strongly.

    Result: The conjecture is false. Let

    G=K7,7.G=K_{7,7}.

    Then ∣V(G)∣=14|V(G)|=14, and Gˉ=K7⊔K7\bar G=K_7\sqcup K_7.

    First, ρ⊥(K7,7)=4\rho^\perp(K_{7,7})=4. A representation in R4=R2⊕R2\mathbb R^4=\mathbb R^2\oplus\mathbb R^2 is obtained by putting the seven vertices in one part on seven distinct nonorthogonal lines in the first R2\mathbb R^2, and the seven vertices in the other part on seven distinct nonorthogonal lines in the second R2\mathbb R^2. Cross-part lines are orthogonal, and within-part lines are not. Conversely, since each part has at least two distinct projective lines, the two parts must occupy mutually orthogonal subspaces of dimensions at least 22 and 22, so dimension at least 44 is necessary.

    Second, ρ⊥(K7⊔K7)=7\rho^\perp(K_7\sqcup K_7)=7. A clique of size 77 needs seven mutually orthogonal nonzero lines, so dimension at least 77 is necessary. In R7\mathbb R^7, take one component represented by the standard basis lines [ei][e_i]. Take the other component represented by the columns of an orthogonal 7×77\times7 matrix with no zero entries, for example the Householder matrix

    Q=I−170uuT,u=(1,2,3,4,5,6,7)T.Q=I-\frac{1}{70}uu^T,\qquad u=(1,2,3,4,5,6,7)^T.

    Its columns are mutually orthogonal, and every inner product eiTqje_i^Tq_j is nonzero, so there are no unwanted cross-component orthogonalities.

    Therefore

    ρ⊥(G)+ρ⊥(Gˉ)=4+7=11,\rho^\perp(G)+\rho^\perp(\bar G)=4+7=11,

    but

    ∣V(G)∣−2=14−2=12.|V(G)|-2=14-2=12.

    Thus

    ρ⊥(G)+ρ⊥(Gˉ)<∣V(G)∣−2,\rho^\perp(G)+\rho^\perp(\bar G)<|V(G)|-2,

    contradicting the lower bound. The conjecture is disproved.

    Citation: No external resolution used. Conjecture source: Solís-Encina and Portillo, “Orthogonal Representation of Graphs,” arXiv:1504.03662, Conjecture 4.2.

  2. Read by a language model on #1 · not a proof

    model says: correctGPT-5.5 xhigh (SMD judge 1)

    scope Full solution as submitted; SMD novelty classification TYPE1

    PASS

    The counterexample is valid. For G=K7,7G=K_{7,7}, Gˉ=K7⊔K7\bar G=K_7\sqcup K_7, ρ⊥(K7,7)=4\rho^\perp(K_{7,7})=4 under the paper’s projective-line convention, and ρ⊥(K7⊔K7)=7\rho^\perp(K_7\sqcup K_7)=7 via two orthonormal bases with all cross inner products nonzero. Hence

    ρ⊥(G)+ρ⊥(Gˉ)=11<14−2,\rho^\perp(G)+\rho^\perp(\bar G)=11<14-2,

    so the conjectured lower bound is false. I found no prior published resolution in the available searches.

    Novelty assessment

    TYPE1

    Classification rationale: This is a genuinely useful correction, but very minor: a simple counterexample to a low-visibility conjecture in an unpublished/working arXiv note. The construction is essentially an elementary complete-bipartite example, using the paper’s own value ρ⊥(Km,n)=4\rho^\perp(K_{m,n})=4 plus a standard generic-orthogonal-basis argument for K7⊔K7K_7\sqcup K_7. It would not support a standalone combinatorics paper, except perhaps as part of an erratum or broader note.

    Literature check: I found no published or open-access source explicitly refuting Conjecture 4.2 or giving this K7,7K_{7,7} counterexample. I checked the arXiv record and updates, arXiv trackbacks, SciRate, alphaXiv, GitHub/user/repository searches, StackExchange/MathOverflow-style queries where accessible, and searches for the exact title, ρ⊥\rho^\perp, the Nordhaus-Gaddum-type inequality, K7,7K_{7,7}, and related “faithful orthogonal representation” terminology. The arXiv paper has no newer correction or journal version visible, no arXiv trackbacks, and SciRate lists no comments.

    Citation: Alberto Solís-Encina and José Ramón Portillo, “Orthogonal Representation of Graphs,” arXiv:1504.03662, Conjecture 4.2.

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