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Statement

It meets ρ⊥(G)>ρ⊥(Vc)\rho^{\perp}(G)>\rho^{\perp}(V_{c}) if it meets the following: - ρ⊥(Vc)>ρ⊥(A)\text{- }\rho^{\perp}\left(V_{c}\right)>\rho^{\perp}(A) - ρ⊥(Vc)>ρ⊥(B)\text{- }\rho^{\perp}\left(V_{c}\right)>\rho^{\perp}(B) - ρ⊥(Vc)≤ρ⊥(A)+ρ⊥(B)\text{- }\rho^{\perp}\left(V_{c}\right)\leq \rho^{\perp}(A)+\rho^{\perp}(B)

Record

Source
  • Working in progress: Orthogonal Representation of Graphs
  • FAR
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No person has examined this. Everything below was judged by machines. say whether it holds →

  1. exploration by a model · #1

    GPT-5.5 xhigh

    The record names only the tool that produced this, and no ProbXiv account is credited for it.

    AI involvement
    ai discovered
    — the result was found by a model.

    NEW

    Problem: Reconstructed statement: for a finite simple graph GG, let VcV_c be an independent vertex cut in Gˉ\bar G, and let A,BA,B be the two components of Gˉ−Vc\bar G-V_c. The conjecture claims that

    ρ⊥(G)>ρ⊥(G[Vc])\rho^\perp(G)>\rho^\perp(G[V_c])

    whenever

    ρ⊥(G[Vc])>ρ⊥(G[A]),ρ⊥(G[Vc])>ρ⊥(G[B]),ρ⊥(G[Vc])≤ρ⊥(G[A])+ρ⊥(G[B]).\rho^\perp(G[V_c])>\rho^\perp(G[A]),\quad \rho^\perp(G[V_c])>\rho^\perp(G[B]),\quad \rho^\perp(G[V_c])\le \rho^\perp(G[A])+\rho^\perp(G[B]).

    Here ρ⊥\rho^\perp is the real faithful/projective orthogonal rank used in the paper: vertices are assigned distinct non-proportional nonzero vectors, and adjacency is exactly orthogonality.

    Result: The conjecture is false.

    Let GG have vertex partition

    A={a0,a1,a2,a3},B={b1,b2,b3},Vc={c1,c2,c3,c4}.A=\{a_0,a_1,a_2,a_3\},\quad B=\{b_1,b_2,b_3\},\quad V_c=\{c_1,c_2,c_3,c_4\}.

    Define GG by the following faithful representation in R4\mathbb R^4:

    a0=e1,a1=e1+e2,a2=e1−e2,a3=e1+2e2,b1=e3+e4,b2=e3−e4,b3=e3+2e4,c1=e1+e3,c2=e1−e3,c3=e2+e4,c4=e2−e4.\begin{aligned} a_0&=e_1,& a_1&=e_1+e_2,& a_2&=e_1-e_2,& a_3&=e_1+2e_2,\\ b_1&=e_3+e_4,& b_2&=e_3-e_4,& b_3&=e_3+2e_4,\\ c_1&=e_1+e_3,& c_2&=e_1-e_3,& c_3&=e_2+e_4,& c_4&=e_2-e_4. \end{aligned}

    Put an edge exactly when the corresponding dot product is 00.

    Then VcV_c induces K4K_4, so

    ρ⊥(G[Vc])=4.\rho^\perp(G[V_c])=4.

    Also G[A]G[A] and G[B]G[B] each contain exactly one edge plus isolated vertices, hence each has faithful orthogonal rank 22:

    ρ⊥(G[A])=ρ⊥(G[B])=2.\rho^\perp(G[A])=\rho^\perp(G[B])=2.

    Thus the conjecture’s hypotheses hold:

    4>2,4>2,4≤2+2.4>2,\qquad 4>2,\qquad 4\le 2+2.

    But the displayed vectors give a faithful orthogonal representation of all of GG in R4\mathbb R^4, so ρ⊥(G)≤4\rho^\perp(G)\le4. Since GG contains the clique K4=G[Vc]K_4=G[V_c], every faithful orthogonal representation needs dimension at least 44. Therefore

    ρ⊥(G)=4=ρ⊥(G[Vc]),\rho^\perp(G)=4=\rho^\perp(G[V_c]),

    contradicting the conjectured strict inequality.

    Moreover, the cut-set context is satisfied: in Gˉ\bar G, VcV_c is independent, Gˉ−Vc\bar G-V_c has precisely the two connected components AA and BB, and Gˉ\bar G is even 44-connected, with VcV_c a vertex cut.

    Citation: No known prior disproof is being invoked; this is an explicit counterexample to Conjecture 5.2 of Solís Encina–Portillo, “Orthogonal Representation of Graphs,” arXiv:1504.03662.

  2. Read by a language model on #1 · not a proof

    model says: correctGPT-5.5 xhigh (SMD judge 1)

    scope Full solution as submitted; SMD novelty classification TYPE1

    PASS

    The counterexample attacks the correct Conjecture 5.2. The displayed vectors define a faithful orthogonal representation in R4\mathbb R^4. They make VcV_c a K4K_4, so ρ⊥(Vc)=4\rho^\perp(V_c)=4; AA and BB each induce one edge plus isolated vertices, so each has faithful orthogonal rank 22. Thus the three hypotheses hold.

    Since the same vectors represent all of GG in dimension 44, while the K4K_4 forces dimension at least 44, ρ⊥(G)=4=ρ⊥(Vc)\rho^\perp(G)=4=\rho^\perp(V_c), contradicting the conjectured strict inequality. The complement cut-set condition is also satisfied. I found no evidence of a prior published disproof in the accessible literature/search results.

    Novelty assessment

    TYPE1

    Classification rationale: This appears to be a genuinely new explicit counterexample, but it is a minor contribution. It refutes a specific conjecture from an obscure 2015 “working in progress” arXiv note, using a small constructed faithful orthogonal representation. The result is useful as a correction/erratum-style observation, but unlikely to support a standalone combinatorics paper.

    Literature check: I found no prior published or online disproof of Conjecture 5.2. Searches by exact title, arXiv ID 1504.03662, author names, “Conjecture 5.2,” “rho^\perp,” and related faithful/orthogonal-rank terminology led back essentially to the original arXiv preprint and the author’s GitHub repository for associated code. GitHub repository/issue/discussion searches showed no existing counterexample or discussion. I found no stronger known theorem implying this counterexample.

    Citation: Alberto Solís-Encina and José Ramón Portillo, “Orthogonal Representation of Graphs,” arXiv:1504.03662, 2015.

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